Question

Find the length of shadow on the ground of a pole of height 6m when the angle of elevation theta of the sum is such that tan Theta is 3by 4

Answer 1

Answer

Length of Shadow is 8 m

Solution

Given that :-

Height of pole = 6m

tan theta = 3/4

Let , Length of Shadow = x m

Now we are provided with tan theta and we know that

$\tan( \theta) = \frac{perpendicular}{base}$

Here putting required values :-

$= > \frac{3}{4} = \frac{6}{x}$

$= > 3x = 24$

$= > x = \frac{24}{3}$

$= > x = 8$

So the value of x is 8m

Answer 2

Answer:

Step-by-step explanation:-

Given; AB= 6m

And angles of elevation of theta

Tan theta= 3/4

We know that; Tan theta = perpendicular/base.

Then let; length of shadow = x

Now;

Tan theta= perpendicular/ base.

So; 3/4 = 6/x

=> 3x = 24

=> x= 24/3

=> x= 8

At last length of shadow of pole is = 8m