Question

Find the length of the base of a triangle having area 155cm2 and altitude 23.5cm.

Answer 1

use the formula 1/2×b×h

1/2×b×23.5=155

b/2=155/23.5

b/2=6.6(round of value)

b=13.2cm

answer is checked

Answer 2

The length of the base of a triangle(b) is 13.2 cm.

Step-by-step explanation:

Given,

The area of triangle = 155 $cm^2$ and

The altitude of triangle(h) = 23.5 cm

To find, the length of the base of a triangle(b) = ?

We know that,

The area of the triangle $=\dfrac{1}{2}$ × Base(b) × Height(h)

⇒ $\dfrac{1}{2}\times b \times 23.5=155$

⇒ $b \times 23.5=155\times 2$

⇒ b × 23.5 = 310

⇒ b = $\dfrac{310}{23.5}$

⇒ b = 13.19 ≈ 13.2 cm

∴ The length of the base of a triangle(b) = 13.2 cm

Thus, the length of the base of a triangle(b) is 13.2 cm.