Question

find the length of the diagonal of a rectangular of length 30m and width 16m.​

Answer 1

Answer:

34m

Step-by-step explanation:

Let length=a= 30m

and width=b=16m

and length of diagonal=c=?

So, by pythagoras theorem

c^2=a^2+b^2

c^2=900+256

c^2=1156

so, c=34 metres

hence, the length of the diagonal of a rectangle of length 30m and width 16m would be 34m

Answer 2

Given:

• Length of rectangle is 30m
• Breadth(width) of rectangle is 16m

To find:

• Length of diagonal of rectangle

Solution:-

We are given that length and breadth of rectangle is 30m and 16m respectively.

To find length of diagonal of rectangle,

We know that:

• $\large{\bf{Diagonal\:=\:({\sqrt{L²+B²)}}}}$

Where,

• L is length of rectangle
• B is breadth of rectangle

Put known value in formula :

$\large{\bf{Diagonal\:=\:({\sqrt{L²+B²})}}}$

$\implies\large{\bf{Diagonal\:=\:({\sqrt{30²+16²})}}}$

$\implies\large{\bf{Diagonal\:=\:({\sqrt{900+256})}}}$

$\implies\large{\bf{Diagonal\:=\:({\sqrt{1156})}}}$

$\implies\large{\bf{Diagonal\:=\:34}}$

Therefore,

• $\large{\boxed{\green{\mathfrak{Diagonal\:of\: rectangle\:is\:\sf{34m}}}}}$