Question

find the lower limit of class interval whose upper limit is 49 and mid value is 44.5​

Answer 1

⇒ Let upper limit and lower limit be x and y

⇒

2

x+y

=42 [ Given ]

∴ x+y=84 ------ ( 1 )

Now, according to the question,

⇒ x−y=10 ------ ( 2 )

Adding equation ( 1 ) and ( 2 ) we get,

2x=94

∴ x=47

And 47−y=10

∴ y=37

∴ Required class interval =37−47

Answer 2

Answer:

40

Step-by-step explanation:

mid value=(upper limit + Lower limit) /2

44.5 = (49+lower limit) /2

44.5 X 2 = (49+lower limit)

89 - 49 = lower limit

40 = lower limit

do lower limit = 40