Question

Find the magnitude of the force applied to a blockof mass 5 kg at rest if it moves 36 m in the first 6seconds. Neglect the force of friction.​

Answer 1

Answer:

Given:

Mass (m) = 5 kg

Initial Velocity (u) = 0 m/s

Distance travelled (d) = 36 m

Time taken to travel the distance (t) = 6 s

Taking out the Final Velocity of the block:

Speed = distance/time

= 36/6

= 6 m/s

Taking out the acceleration:

a = (v - u)/t

a = (6 - 0)/6

a = 1 m/s

Force = Mass × Acceleration

Force = 5 × 1

Force = 5 N

Hope it Helps!!