Find the mass of 11.2 L of ammonia gas at NTP
Answers
Answer:
1 mole of NH3 at STP occupies volume of 22.4l
1 mole of NH3 weights= molar mass =17g
so 17g of NH3 =22.4l
let 17g of NH3 =22.4l
let xg of NH3= 11.21
therefore, x= (11.2×17)/(22.4)
=8.5g
Answer:
The mass of the 11.2L of ammonia gas at NTP IS 8.5g
Explanation:
STP is the standard temperature and pressure and NTP is the normal temperature and pressure. As per IUPAC, the STP value of temperature and pressure for gas is 273.15 K and 0.987 atm respectively. The NTP value of temperature and pressure is 293.15 K and 1atm.
GIVEN THAT :
volume of ammonia (V) = 11.2 lit
molar volume (Vm) = 22.4 lit/ mol
therefore, number of moles (n) = V/Vm
= 11.2/22.4 moles.
= 0.5 moles.
molar mass of ammonia (M) = 17 g/moles
therefore, mass of 0.5 moles = n × M
= 0.5 × 17g
=8.5 g
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