Chemistry, asked by seenarajagopalan3, 11 months ago

Find the mass of 11.2 L of ammonia gas at NTP​

Answers

Answered by ruchikshirsagar
8

Answer:

1 mole of NH3 at STP occupies volume of 22.4l

1 mole of NH3 weights= molar mass =17g

so 17g of NH3 =22.4l

let 17g of NH3 =22.4l

let xg of NH3= 11.21

therefore, x= (11.2×17)/(22.4)

=8.5g

Answered by kshitijgrg
1

Answer:

The mass of the 11.2L of ammonia gas at NTP IS 8.5g

Explanation:

STP is the standard temperature and pressure and NTP is the normal temperature and pressure. As per IUPAC, the STP value of temperature and pressure for gas is 273.15 K and 0.987 atm respectively. The NTP value of temperature and pressure is 293.15 K and 1atm.

GIVEN THAT :

volume of ammonia (V) = 11.2 lit

molar volume (Vm) = 22.4 lit/ mol

therefore, number of moles (n) = V/Vm

                                                    = 11.2/22.4 moles.

                                                     = 0.5 moles.

molar mass of ammonia (M) = 17 g/moles

therefore, mass of 0.5 moles = n × M

                                                 = 0.5 × 17g

                                                 =8.5 g

#SPJ2

Similar questions