find the maximum or minimum values of the function
y=x+1/x for x > 0
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hii friend
here is ur answer...
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solution:-
======
y=x +1/x
dy/dx=1-1/x^2
☆☆☆☆☆☆☆☆
for y to be maximum or minimum ,
dy/dx=0
or, :1-1/x^2=0
thus , x=1 or -1
☆☆☆☆☆☆
for x > 0 the only possible maximum or minimun is at x=1
◆◆◆
At x=1 , y=x+1/x is very large because of the term 1/x.For very large x again y is very large because of the term x.
◇◇◇
Thus x=1 must correspond to a minimum .Thus, y has only a minimum for x > 0.
■■■
This minimum occurs at x =1 and the minimum value of y is =2.
□□□□□
hope it will help you♡♡♡♡♡♡
BE BRAINLY. ..
BY silu12@....
☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆→→☆→☆☆☆☆☆☆
here is ur answer...
♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡
solution:-
======
y=x +1/x
dy/dx=1-1/x^2
☆☆☆☆☆☆☆☆
for y to be maximum or minimum ,
dy/dx=0
or, :1-1/x^2=0
thus , x=1 or -1
☆☆☆☆☆☆
for x > 0 the only possible maximum or minimun is at x=1
◆◆◆
At x=1 , y=x+1/x is very large because of the term 1/x.For very large x again y is very large because of the term x.
◇◇◇
Thus x=1 must correspond to a minimum .Thus, y has only a minimum for x > 0.
■■■
This minimum occurs at x =1 and the minimum value of y is =2.
□□□□□
hope it will help you♡♡♡♡♡♡
BE BRAINLY. ..
BY silu12@....
☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆→→☆→☆☆☆☆☆☆
apk13:
fabolus
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