Find the maximum volume of a right circular cylinder if the sum of its radius and height is 6 units.
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Let height of cylinder be h and radius be r
=>r+h=6
=>h=6-r
Volume of cylinder V =pi *r^2*h
Pi*r^2*(6-r)
Pi*(6r^2-r^3)
For maximum or minimum volume
dv/dr should be equals to zero
dv/dr =pi(12r-3r^2) =0
12r=3r*r
r=4
Put value of r in given equation
R+h=6
h=2
Volume of cylinder =pi(4)^2*(2)
Pi*(16)*(2)
32pi is maximum volume
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