Find the measure of an angle which is 36deegree more than its complement
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If we let the smaller angle as X
According to the question,
(X + 36)+X=90°
So,
2X =(90-36)°
→ X = 27°
So, the angle which is 36° more than its complement is 63°
According to the question,
(X + 36)+X=90°
So,
2X =(90-36)°
→ X = 27°
So, the angle which is 36° more than its complement is 63°
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