Question

Find the polynomial having two zeroes are -3/2 and 3/5

Answer 1

Solution:-

given by:-

having two zeroes are -3/2 and 3/5

by formula:-

${x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0 \\ {x}^{2} - ( \frac{ - 3}{2} + \frac{3}{5} )x + (\frac{ - 3}{2} \times \frac{3}{5} ) = 0 \\ \\ {x}^{2} - ( \frac{ - 15 + 6}{10} ) x - \frac{9}{10} = 0 \\ {x}^{2} + \frac{9x}{10} - \frac{9}{10} = 0 \\ \\ \frac{10 {x}^{2} + 9x - 9}{10} = 0 \\ \\ ( 10 {x}^{2} + 9x - 9 = 0)ans$