find the measure of an angle which is twice of its compliment (full process)
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Let the first angle be x. Let the second angle be 2x. ACC. To question x+2x= 90 = 3x = 90 = x = 90/3 = 30. x = 30. 2x = 60
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Let the angle be x
then, it's complement will be 90-x
According to the question,
x=2(90-x)
x=180-2x
3x=180
x=60
The angle is 60°
Verification:
complement of angle 60° is 30°(90°-60°)
it can be clearly seen that the angle is twice of it's complement
then, it's complement will be 90-x
According to the question,
x=2(90-x)
x=180-2x
3x=180
x=60
The angle is 60°
Verification:
complement of angle 60° is 30°(90°-60°)
it can be clearly seen that the angle is twice of it's complement
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