Question

Find the median of the following data:-

spam:-strict action will be taken/don't be greedy!!

$\bullet \sf{cumulative \:frequency \: given\:for \:help}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c|c}\sf Class\: interval&\sf Frequency\: (f)&\sf \: cumulative \: frequency\\\frac{\qquad \qquad}{}&\frac{\qquad \qquad}{}\\\sf 0 - 10&\sf 5&\sf5\\\\\sf 10 - 20 &\sf 8&\sf13\\\\\sf 20-30 &\sf 8&\sf21\\\\\sf 30 - 40&\sf 15&\sf36\\\\\sf 40-50&\sf 16&\sf52\\\\\sf 50-60&\sf 6&\sf58\\\frac{\qquad}{}&\frac{\qquad}{}\\\sf & \sf & \end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$​

Answer 1

Answer:

"Many people in California figured gold was there, but it was James W. Marshall on January 24, 1848, who saw something shiny in Sutter Creek near Coloma, California. He had discovered gold unexpectedly while overseeing construction of a sawmill on the American River."

Answer 2

Answer:

10 ka mediam hai

Step-by-step explanation:

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