Find the molality of the solution if it contains 7.5g of Na2So4 if the mass of solution is 800g?
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atomic mass of Na2SO4 =142
molality = moles of solute upon mass of solution{ in kg}
mole = 7.5/142 =0.5
molality = 0.5/0.8=0.06
molality = moles of solute upon mass of solution{ in kg}
mole = 7.5/142 =0.5
molality = 0.5/0.8=0.06
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Molality (m) = no of moles of solute / wt of solvent (kg)
no of moles = wt/ molecular wt
=7.5/142
=7.5 /142 /792.5 *10^ - 3
=7.5 / 142*0.8
=7.5 /112.6
=0.066 mol / kg
Buddy this is ur ans
no of moles = wt/ molecular wt
=7.5/142
=7.5 /142 /792.5 *10^ - 3
=7.5 / 142*0.8
=7.5 /112.6
=0.066 mol / kg
Buddy this is ur ans
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