find the molecular weight of my Zn(NO3)2
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Answer:
molecular weights for each element:
Zn=65.38 g/mol
N=14.01 g/mol
O=16.00 g/mol
The molecular weight of zinc nitrate is then: 1*(65.38)+2*(14.01)+6*(16.00)=189.40 g/mol.
Using a conversion formula to calculate moles of zinc nitrate:
163.97 gZn(NO3)2 × {1 mol Zn(NO3)2}/189.40
= 0.866 mol Zn(NO3)2
There are 0.866 moles of zinc nitrate.
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