Question

find the moment of inertia of your bed room wall at an axis through the centre of the wall and at one end and also rind the moment of inertia perpendicular to the wall.​ also find the relationship between them if it's mass/ m^2 is 500gm

Answer 1

Answer:

Explanation:

Let's say that the wall's height = h

                                       length = l

                                       mass = m

Therefore, MoI about an vertical axis passing through its center and parallel to it is = (m*l^2)/12

MoI about an horizontal axis passing through its center and parallel to it is = (m*h^2)/12

MoI about vertical end = (m*l^2)/3

MoI about horizontal end = (m*h^2)/3

MoI about an axis passing through its center and perpendicular to it = m[(l^2/12)+(h^2/12)].

Hope this helps.