Question

find the mth term of an arithmetic progression whose 12th term exceed the 5th term by 14 and the sum of both terms in 36

Answer 1

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Answer 2

Step-by-step explanation:

12th term=a+11d

5th term = a+4d

according to question

(a+11d)-(a+4d)=14

7d=14

d=2

also (a+11d)+(a+4d)=36

putting the value of d and solving for a we get

a=3

mth term=a+(m-1d)

mth term =1+2m