Question

Find the nature of quadratic equation 2x2-6x+3=0

Answer 1

Answer:

Step-by-step explanation:

Step 1

Find Discriminant, D using the formula D = b^{2} -4ac

where a = 2, b = -6 and c = 3

Step 2

If D = 0, then real and equal roots

If D> 0, Real and distinct roots

If D< 0, Imaginary roots

$D = b^{2} -4ac$

= $(-6)^{2} -4*2*3\\= 36-24\\=12 > 0$

Hence D>0, therefore the quadratic equation has 2 real and distinct roots.