Question

find the nature of the roots of the quadratic equation 2x^2+3√2-4=0​

Answer 1

Step-by-step explanation:

D=b^2-4ac

=(3√2)^2-4(2)(-4)

=18+32

=50

Now as D>0

the equation has two unique roots.

HOPE YOU LIKE MY ANSWER AND MARK ME THE BRAINLIEST!!!!