Question

Find the nth term of this number sequence
1,7,13,19

Answer 1

Answer:

the nth term of this number sequence 1,7,13,19 is 6n-5.

Answer 2

$\underline{ \underline{ \frak{ \pink{question}}}}$

Find the nth term of this number sequence

1 , 7 , 13 , 19.

$\underline{ \underline{ \frak{ \pink{solution}}}}$

As we can see

First term of sequence, a = 1

common difference of sequence, d = 6

Since, it forms AP

so,

$\rm{a_n=a+(n-1)d}$

substituting known values

$\rm{a_n=1 + ( n - 1)6}$

so,

nth term of sequence will be

$\boxed{\bf{a_n=6n-5}}$