Question

find the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8,15 and 21.

Answer 1

109200 is the answer..... I guess

Answer 2

the no which is divisible by 8 15 21  also divisible by lcm of 8 15 21 .
lcm =840
110000can be divided by 840
Find the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8,15 and 21=109200 you will have to subtract the remender of the number we dividedwith the no 110000.