find the number of ammonia find the number of NH3 molecules present in 0.051 g of ammonia
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hey mate here is your answer
molecular mass= 2*27+3*16=102 g 102 g= 1 mole so 0..51g =>1/102*0.51 mole=0.0005 mole 1 mole of ----=2 * av no. =>0.0005mole = 2*0.0005*6.022*10 23=6.022*10 20atoms
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molecular mass= 2*27+3*16=102 g 102 g= 1 mole so 0..51g =>1/102*0.51 mole=0.0005 mole 1 mole of ----=2 * av no. =>0.0005mole = 2*0.0005*6.022*10 23=6.022*10 20atoms
hope...it...helps...
mark me as a brainlist....mate
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