Question

Find the number of bricks,each measuring 25cm×12.5cm×7.5cm,required to construct a wall 24m long 20m high and 0.5m thick.while the cement and sand mixture occupies 1/20 of the volume of the wall

Answer 1

volume of brick = 25×12.5×7.5
$25 \times 12 .5 \times 7.5 = 2343.75$
v of n number
volume of wall =2400×2000×50=240000000
volume of cement =1/20of volume of wall
so volume of total number of bricks =1/8volume
wall
=
$1 \div 8 0\times 2343.75 = 3000000$


v of n number of bricks=v of remaining wall

$n \times 2343.75 = 3000000$
$n = 1280$

Answer 2

Answer:

volume of brick = 25×12.5×7.5

25 \times 12 .5 \times 7.5 = 2343.7525×12.5×7.5=2343.75

v of n number

volume of wall =2400×2000×50=240000000

volume of cement =1/20of volume of wall

so volume of total number of bricks =1/8volume

wall

=

1 \div 8 0\times 2343.75 = 30000001÷80×2343.75=3000000

v of n number of bricks=v of remaining wall