Find the number of coin whose diameter is 1.5 and 0.2 thick if it is melted to form right circular cylinder of height 10 and diameter 4.5
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Each one of those coins is also a cylinder (just a very very short one), and its volume is
V = πr²h = π(.75)²(.2) = 9π/80 cm³
The right circular cylinder has volume V = π(2.25)²(10) = 405π/8 cm³.
Divide the larger cylinder's volume by the volume of each coin = (405π/8) / (9π/80) = 450 coins
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