find the number of molecules and atoms in 112ml O3 gas at STP
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22400 ml contains 6• 10^23 molecules
112 ml ----→ 6*10^23 *112/22400. ( unitary method
== 3*10^21 molecules
no of atoms in 1 molecule = 3
total atoms = 3*3*10^21=9*10^21
112 ml ----→ 6*10^23 *112/22400. ( unitary method
== 3*10^21 molecules
no of atoms in 1 molecule = 3
total atoms = 3*3*10^21=9*10^21
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