Find the number of solutions of equation:- sec²xcosec²x+2cos²x=0
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Answer:
In △ABC AB=AC
⇒∠B=∠C (Angles opposite to equal sides are equal)
Now using angle sum property
∠A+∠B+∠C=180
∘
⇒80
∘
+∠C+∠C=180
∘
⇒2∠C=180
∘
−80
∘
⇒∠C=
2
100
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=50
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now ∠C+∠x=180
∘
(Angles made on straight line (AC) are supplementary)
⇒50
∘
+∠x=180
∘
⇒∠x=180
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−50
∘
=130
∘
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