Math, asked by ajeetroy5276, 1 year ago

Find the number of terms of an ap if the last term is 43 first term is 7 and the common difference is6

Answers

Answered by neosingh
6
a(n) = a + (n-1)d
here
a = 7
a(n) = 43
d = 6
n= ??
put the values
43 = 7 +(n-1)*6
43-7= 6n -6
36+6 = 6n
n = 7 ans
Answered by Dima
2
If this is an arithmetic sequence. Then,

a= 7 , d= 6 , L (Tn) = 43

Tn = a+ (n-1) d

43 = 7 + (n-1) x 6

43 = 7 + 6n - 6

1 + 6n = 43

6n = 43 -1

6n = 42

n = 42/6

n = 7

No. Of terms of the sequence is 7.

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