Question

Find the number which divides 167 and 95 leaving 5 as remainder solve it ​

Answer 1

Answer:18

Step-by-step explanation:First: If any number which is dividing both of them leaves remainder then ,in these type of question subtract it from the numbers given, like in this question 167 and 95 are given leaving reainder 5 respectively.

167-5=162

95-5=90

By Euclid's division algorithm it's can be done or simply the HCF of both numbers can be taken.

162>90

162=90×1+72

r(remainder) not equals to 0

90=72×1+18

r not equals to 0

72=18×4+0

r=0

18 is the HCF of 162 and 90

18 is the number which when divides 167 and 95 leaves remainder 5.

Answer 2

Answer:

The required number is 18.

Step-by-step explanation:

To find:-

The number which divides $167$ and $95$ leaving $5$ as remainder.

Step 1 of 1

Since the numbers $167$ and $95$ leaves the remainder $5$.

So, subtract the number 5 from both the numbers.

⇒ 167 - 5 = 162

⇒ 95 -5 = 90

Notice that the HCF of the numbers 162 and 90 will divide both the numbers.

Apply Euclid's division algorithm to 162 and 90, we get

162 = 90 × 1 + 72

This implies the remainder is non-zero.

So, again apply the Euclid's division algorithm to 90 and 72, we get

90 = 72 × 1 + 18

Since the remainder is again non-zero.

Apply the Euclid's division algorithm to 72 and 18, we get

72 = 18 × 4 + 0

Here, remainder is 0.

Thus, the HCF of 162 and 90 is 18.

Final answer: The number 18 divides $167$ and $95$ leaving $5$ as remainder.

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