Question

find the obsolute refractive index of the water critical angle 48.5

Answer 1

n=1/sinc. here sinC is 48.5

Answer 2

relation between refractive index of a substance and it's critical angle is ,,,, refractive index of water = 1÷ sin C (here C is the critical angle ) hence ,,,refractive index of water= 1÷sin(48.5)=1÷0.981= 1.01=1 (approx) therefore the absolute refractive index of water is 1
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