Find the oxidation no. of Na2S4O8 OF SULPHUR
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oxidation no. of Na= +1
oxidation no. of O= -2
let oxidation no. of S=x
2(+1)+ 4x+ 8 (-2) = 0
2 + 4x -16=0
4x= 14
x=7/2 --> fractional oxidation state of S
fractional oxidation state is the average oxidation state when an element exists in more than 1 oxidation states in a compound.
oxidation no. of O= -2
let oxidation no. of S=x
2(+1)+ 4x+ 8 (-2) = 0
2 + 4x -16=0
4x= 14
x=7/2 --> fractional oxidation state of S
fractional oxidation state is the average oxidation state when an element exists in more than 1 oxidation states in a compound.
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