find the parallel sides of trapeziun whose area is 475sq.cm and height is 19cm.one parallel side is greater than the other by 4cm
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let one parallel side be x then other will be x+4
now,
we know that area of trapezium =1/2(sum of parallel sides)×height
so,
474=1/2×(x+x+4)×19
474=1/2×2x+4×19
474=2x+2×19
474=2x+38
x=(474-38)/2
=436/2
=218cm
hence one parallel side is 218cm and other will be 218+4=222cm.
now,
we know that area of trapezium =1/2(sum of parallel sides)×height
so,
474=1/2×(x+x+4)×19
474=1/2×2x+4×19
474=2x+2×19
474=2x+38
x=(474-38)/2
=436/2
=218cm
hence one parallel side is 218cm and other will be 218+4=222cm.
Muplirajesh:
but area is 475sq.cm ,not 474sq.cm
sry it was done by mistake
u can solve it by putting475 at the place of 474
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