Physics, asked by vijaykumar80661, 6 months ago

Find the percentage change in gravity (acceleration) at a depth 64km from the surface of the earth

Answers

Answered by Anonymous

3

Explanation:

g=(

3

4πGρ

o

)(1−

R

d

) where ρ

o

is the density of earth,R is the radius of Earth, d is depth

So as d increases acceleration due to gravity decreases

pls mark brainlist answer

Previous Question

Next Question

Similar questions

Math, 3 months ago

Find the length of each side of a square whose area is equal to the area of a rectangle of length 14.8m and breadth 3.7m.

Science, 3 months ago

English You have read the poem voyage by Harindranath Chattopadhyay You have to write about the poet based on the points. His childhood days at home School higher education His family history The poets literary works...

Business Studies, 3 months ago

Q1. What does the word ‘blitz’ translate to in German? Q2. What is the contagious disease varicella more commonly known as? Please answer fast without any spam...

Math, 6 months ago

(iv) ऋतु प्रवास का क्या तात्पर्य है? एक शब्द मे उत्त्र...

English, 6 months ago

1 point 5. A statement about the proposed relationship between independent and dependent variablesis known as a O A. hypothesis O B. relationship O C. variable O D. hypotenuse...

Chemistry, 1 year ago

In which of the following reactions, standard entropy change (∆S°) is positive and standard Gibb’s energy change (∆G°) decreases sharply with increase in temperature ? (a) C (graphite) + 1/2 O₂(g) → CO(g) (b) CO(g) + 1/2 O₂(g) → CO₂(g) (c) Mg(s) + 1/2 O₂(g) → MgO(s) (d) 1/2 C (graphite) + 1/2 O₂(g) → 1/2 CO₂(g)...

Chemistry, 1 year ago

In conversion of lime-stone to lime, CaCO₃(s) → CaO(s) +CO₂(g) the values of ∆H° and ∆S° are + 179.1 kJ mol⁻¹ and 160.2 J/K respectively at 298 K and 1 bar. Assuming that ∆H° and ∆S° do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is (a) 1118 K (b) 1008 K (c) 1200 K (d) 845 K.

Chemistry, 1 year ago

Consider the following processes : ∆H (kJ/mol) 1/2 A → B +150 3B → 2C + D –125 E + A → 2D +350 For B + D → E + 2C, ∆H will be : (a) 525 kJ/mol (b) – 175 kJ/mol (c) – 325 kJ/mol (d) 325 kJ/mol...