Question

find the percentage composition of C12 H22 O11 find the composition

Answer 1

Mass-
C12= 12 ×12 = 144,H22 = 1 ×22 = 22, O11= 16×11=176
Molecular mass= 144+22+176 = 342 g
Composition of -
Carbon= 144/342×100 = 42.1 per
Hydrogen = 22/342×100 =6.43 per
Oxygen= 176/342×100= 51.46 per

Answer 2

The percentage composition of carbon, hydrogen and oxygen of C12 H22 O11 is 42.1%, 6.43% and 51.46% respectively.

Given:

A molecule C12 H22 O11.

To Find:

The percentage composition of C12 H22 O11.

Solution:

To find the percentage composition of C12 H22 O11 we will follow the following steps:

As we know,

The molecular weight of C12 H22 O11 = 12×12 + 22×1 + 11×16 = 144 + 22 + 176 = 342 grams.

Also,

Percentage composition of carbon =

$\frac{12 \times 12}{342} \times 100= \frac{144}{342} \times 100 =42.1 %$

Similarly,

Percentage composition of oxygen =

$\frac{11 \times 16}{342} \times 100 = \frac{176}{342} \times 100 =51.46 %$

Percentage composition of hydrogen =

$\frac{22 \times 1}{342} \times 100= \frac{22}{342} \times 100 = 6.43 %$

The percentage composition of carbon, hydrogen and oxygen of C12 H22 O11 is 42.1%, 6.43% and 51.46% respectively.

#SPJ2