Find the percentage error in energy E = \frac{1}{2} mv², where m = (52.4 ± 0.2) kg and v = (25.6 ± 0.1) m/s.
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Answered by
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E= (0.2/52.4) x100 + (2 x 0.1/25.6) x 100
=1.16 %
=1.16 %
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0
Answer:
1.163%
Explanation:
percentage error =(dm+2dv). ×100
m. v.
=(0.2+2×0.1) ×100
52.4. 25.6
=0.2. + 0.2. x 100
52.4. 25.6
=(512 +1048) x 100
52.4x25.6
=15.60x100
52.4x256
=1.166%
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