Question

Find the percentage error in energy E = \frac{1}{2} mv², where m = (52.4 ± 0.2) kg and v = (25.6 ± 0.1) m/s.

Answer 1

E= (0.2/52.4) x100 + (2 x 0.1/25.6) x 100
=1.16 %

Answer 2

Answer:

1.163%

Explanation:

percentage error =(dm+2dv). ×100

m. v.

=(0.2+2×0.1) ×100

52.4. 25.6

=0.2. + 0.2. x 100

52.4. 25.6

=(512 +1048) x 100

52.4x25.6

=15.60x100

52.4x256

=1.166%