find the percentage loss of energy when the key is shifted b to c
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Answer:
When the switch is in position 1, the combination has C and C
0
in parallel and C in series for which the equivalent capacitance is
Ceq=
2C+C
0
C(C+C
0
)
The total charge on the combination is
Q=EC
eq
=
2C+C
0
EC(C+C
0
)
The total charge on the three capacitors can be obtained as
q
3
=EC
eq
=
2C+C
0
EC(C+C
0
)
q
2
=
(2C+C
0
)(C+C
0
)
EC(C+C
0
)C
0
=
2C+C
0
ECC
q
1
=
(2C+C
0
)(C+C
0
)
EC(C+C
0
)C
=
2C+C
0
EC
2
When the switch is in position 2, the charge distribution on the three capacitors is obtained as
q
3
′
=
2C+C
0
EC
2
,q
2
′
=q
2
and q
1
′
=
2C+C
0
EC(C+C
0
)
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