Question

find the perimeter of a rectangle field whose length is 4 times its width and which has area equal to 20736 square metre

Answer 1

let b be its width and l be its length
so L = 4b
l × b = 20736
4b ×b = 20736
5b^2 = 20736
b^2 = 20736/5
b^2 = 4147.2
b = 64.4m (approx.)
l = 4b
l = 257.6m

Answer 2

☆Hello friend☆

Area of rectangle= 4x×x
20736m^2=4x^2
20736m^2/4=x^2
5184m^2=x^2

$\sqrt{5184 {m}^{2} } = x$

72 m=x
So breadth=72m then length=72×4=288m

Perimeter=2(length+breadth)
Perimeter=2(288+72)m
Perimeter= 2×360 m= 720m

Hope it helps

☺☺☺