Question

In triangle PQR,AnglePQR=90°;PQ=3 root3 and PR=6 root3 then find QR

Answer 1

By pythagorous theorem
H^2 =p^2 +b^2
(6root3)^2 =(3root3) ^2 +b^2
108=27+B^2
108- 27=b^2
81=b^2
9=b (qr) is the correct answer

Hope it is helpful..

Answer 2

pr = 6root3 
pq = 3 root3
q = 90
qr = root 81
==9 is answer