Question

find the perimeter of a rectangle if one of its sides is 12 cm and a diagonal is 37 cm​

Answer 1

Hey mate here your answer!!!!

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Answer 2

Given:- If a diagonal of a rectangle is 37 cm and one side is 12 cm .

To Find:- The other side .

Solution :- Given that If a diagonal of a rectangle is 37 cm and one side is 12 cm .

So , the Figure would be something like this ; [ If LaTeX doesn't work on app see the attachment or refer to website ]

$\setlength{\unitlength}{1 cm}\begin{picture}(12,8)\thicklines\put(0,0){\line(6,5){5}}\put(5,4.15){\line(0, - 1){4.15}}\put(5,0){\line(-1,0){5}}\put(0,4.15){\line(1,0){5}}\put(0,4.149){\line(0,-1){4.149}}\put(0,-0.3){ \tt A }\put(5,-0.3){ \tt B }\put(5,4.46){ \tt C }\put(0,4.46){ \tt D }\put(4.8,0){\line(0,1){0.2}}\put(4.8,0.2){\line(1,0){0.2}} \put(5.3,2){ \sf 12 cm }\put(1.5,2.2){ \sf 37 cm }\end{picture}$

→ So , In ∆ ABC ;

⇒ AC² = AB² + BC²

⇒ ( 37 cm )² = AB² + ( 12 cm )²

⇒ 1369cm² = AB² + 144cm².

⇒ AB² = 1369 cm² - 144 cm²

⇒ AB² = 1225 cm².

⇒ AB = √ 1225 cm²

⇒ AB = 35 cm .

→Hence the value of other side is 35 m .

Now , Perimeter = 2 ( lenght + breadth )

= 2 ( 35 cm + 12 cm )

= 2 × 47 cm

= 94 cm.

★ Hence the perimeter is 94 cm ★

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