Question

find the perimeter of a rectangle whose length is 126 meter and breadth is 4/7 of length

Answer 1

l =126m
b=4/7 of length
= 4/7×126
b= 72m
$perimeter = 2(l + b) \\ = 2(126 + 72) \\ = 2 \times 198 \\ 396m$