find the perimeter of a rectangular feild whose breadth is 42.5 cm ans its length is double of the breadth
Answers
Answered by
1
PERIMETER OF RECTANGLE= 2(l+b)
=2(42.5*2+42.5)
=2(85+42.5)
=2*3612.5
=7225.
Hence, the perimeter of rectangular field is 7225cm.
=2(42.5*2+42.5)
=2(85+42.5)
=2*3612.5
=7225.
Hence, the perimeter of rectangular field is 7225cm.
Answered by
1
Answer:
first we have to find length
length is 2 times of bredth=42.5*2=85
length is 85cm
perimeter of rectangle=2(length+bredth)
=2(85+42.5)cm
=2*127.5 cm
=255 cm
perimeter is 255 cm
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