Question

find the perimeter of a rectangular field whose length is 4times its width and which has area equal to 20736 sq.m​

Answer 1

Answer:

Perimeter of the rectangular field is 720 m

Step-by-step explanation:

Let width of rectangular field is $x$ m

Length of rectangular field is $4x$ m

Area of the rectangle a =  20736 sq.m​

Area is

$A =lb =x\times 4x=20736\\x^2 =\frac{20736}{4} \\x= \sqrt{5184} \\x=72 m$

width of rectangle is 72 m

length of rectangle is 4 x 72 = 288 m

Perimeter of the rectangle is

$=2(l+b)=2(288+72)\\=720 m$

Perimeter of the rectangular field is 720 m

Answer 2

Step-by-step explanation:

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