find the perimeter of a triangle having sides (4x+3y+7)m,(8x+3)m and (3y+7)m
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Answer:
12x + 6y + 17
Step-by-step explanation:
Add all the coefficients of the variables respectively
4x + 8x = 12x
3y + 3y = 6y
7 + 3 + 7 = 17
by combining all above ...
perimeter = 12x + 6y + 17
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