Find the perimeter of an isoceles right angled triangle having an area of 5000m^2.(USE√2=1.41)
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An isoceles right angled triangle is a triangle in which the two equal sides are the base and altitude of that right angled isoceles triangle .
Given,
Area of the triangle = 5,000 m²
Let , the equal sides are of x length.
So,
⇒ Base = x
⇒ Altitude = x
We know that,
⇒ Area of a triangle = ( 1/2 ) × Base × Altitude
⇒ 5,000 m² = ( 1/2 ) x × x
⇒ 5,000 m² = x²/2
⇒ 5,000 m² × 2 = x²
⇒ 10,000 m² = x²
⇒ x = √( 10,000 m² )
•°• x = 100 m
Now we have,
Base = x = 100 m
Altitude = x = 100 m
By Pythagoras Theroem,
⇒ Hypotenuse² = Base² + Altitude²
⇒Hypotenuse² = ( 100 m )² + ( 100 m )²
⇒Hypotenuse² = 100,000 m² + 100,000 m²
⇒ Hypotenuse² = 2 × 100,000 m²
⇒ Hypotenuse = √( 2 × 100,000 m² )
⇒ Hypotenuse = 100√2 m
⇒ Hypotenuse = 100 ( 1.41 )m
•°• Hypotenuse = 141 m
Now,
Perimeter of any triangle = Sum of all three sides
= 100 m + 100 m + 141 m
= 341 m
The required answer is 341 m.
Given,
Area of the triangle = 5,000 m²
Let , the equal sides are of x length.
So,
⇒ Base = x
⇒ Altitude = x
We know that,
⇒ Area of a triangle = ( 1/2 ) × Base × Altitude
⇒ 5,000 m² = ( 1/2 ) x × x
⇒ 5,000 m² = x²/2
⇒ 5,000 m² × 2 = x²
⇒ 10,000 m² = x²
⇒ x = √( 10,000 m² )
•°• x = 100 m
Now we have,
Base = x = 100 m
Altitude = x = 100 m
By Pythagoras Theroem,
⇒ Hypotenuse² = Base² + Altitude²
⇒Hypotenuse² = ( 100 m )² + ( 100 m )²
⇒Hypotenuse² = 100,000 m² + 100,000 m²
⇒ Hypotenuse² = 2 × 100,000 m²
⇒ Hypotenuse = √( 2 × 100,000 m² )
⇒ Hypotenuse = 100√2 m
⇒ Hypotenuse = 100 ( 1.41 )m
•°• Hypotenuse = 141 m
Now,
Perimeter of any triangle = Sum of all three sides
= 100 m + 100 m + 141 m
= 341 m
The required answer is 341 m.
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