Math, asked by mayashriwas9072, 10 months ago

find the perimeter of each of the following shapes take Pi is equal to 3.14 ​

Answers

Answered by Anonymous
8

Answer:

Step-by-step explanation:

Figure 1

radius of both circles = 16 cm / 2

                                   = 8 cm

Perimeter of the figure = Circumference of 2 semicircles + 2 Breadth of the rectangles

                                       = 2 × 1 / 2 × 2 π r + 2 × 3 cm

                                       = 2 π r + 6 cm

                                       = 2 × 3.14 × 8 cm + 6 cm

                                       = 50.24 cm + 6 cm

                                       = 56.24 cm

Perimeter is 56.24 cm

Figure 2

Radius of big semi circle = 8 cm/2

                                         = 4 cm

Radius of small semi - circle = 4 cm / 2

                                               = 2 cm

Perimeter = 4 cm + 3 cm + 3 cm + circumference of the small semicircle + circumference of big semi circle.

= 10 cm + 1/2 × 2 π r + 1/2 × 2 π r

= 10 cm + 3.14 × r + 3.14 × r

= 10 cm + 3.14 × 4 + 3.14 × 2

= 10 cm + 12.56 + 6.28

= 28.84

The perimeter is 28.84 cm

Hope it helps ^__^

Answered by Anonymous
2

(a) Given, radius, r = 14 cm

We know that circumference

=

2

π

r

=

2

×

22

7

×

14

=

2

×

22

×

2

=

88

cm

(b) Given, radius, r = 28 mm,

We know that circumference

=

2

π

r

=

2

×

22

7

×

28

=

2

×

22

×

4

=

176

mm

(c) Given, radius, r = 21 cm

We know that circumference

=

2

π

r

=

2

×

22

7

×

21

=

2

×

22

×

3

=

132

cm

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