Question

find the perimeter of rectangle whose area is 6800 meter and breadth is equals to 34 meter​

Answer 1

$\huge{\underline{\underline{\red{\mathfrak{Answer :}}}}}$

✪ Given :

Breadtg of rectangle(B) = 34 m

Area = 6800 m

_____________________________

✪ To Find :

Perimeter of rectangle

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✪ Solution :

We know that,

$\Large{\boxed{\boxed{\green{\mathfrak{Area = Length \times Breadth}}}}}$

(Putting Values)

6800 = Length * 34

6800/34 = Length

Length = 200 m

$\large{\boxed{\orange{\sf{Length = 200 \: m}}}}$

$\rule{200}{2}$

Now,

$\Large{\boxed{\boxed{\blue{\mathfrak{Perimeter = 2(L + B)}}}}}$

(Putting Values)

Perimeter = 2(200 + 34)

Perimeter = 2(234)

Perimeter = 468 m

$\large{\boxed{\pink{\sf{Perimeter = 468 \: m}}}}$

$\rule{200}{2}$

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#BAL

Answer 2

Answer:

$\huge\underline\mathfrak{Answer\::}$

$\huge{\tt\red{Given\::}}$

● Area of rectangle = 6800 sq.m

● Breadth = 34 m

$\huge{\tt\orange{To\:find\::}}$

● Perimeter of rectangle

$\huge{\tt\green{Solution\::}}$

$\large{\boxed{Area=l \times b}}$

$\longrightarrow$6800= l × 34

$\longrightarrow$l = 6800/34

$\longrightarrow$ l = 200

$\large{\boxed{Perimeter=2(l\:+b)}}$

$\longrightarrow$Perimeter = 2(200+34) m

$\longrightarrow$Perimeter = (2 × 234 )m

$\longrightarrow$Perimeter = 468 m

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