FIND THE PERIMETER OF RECTANGLE WHOSE LENGTH IS 40 CM AND DIGONAL IS 41 CM
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➡ Heya Friend
✔ Let the breadth be x cm
✔ Length of Rectangle ( Base ) = 40 cm
✔ Diagonal ( Hypotenuse ) = 41 cm
✔ Using Pythagoras Theorem
➡ ( H )² = ( A )² + ( B )²
➡ ( 41 )² = ( x )² + ( 40 )²
➡ ( 1681 ) = ( x )² + ( 1600 )
➡ ( 1681 - 1600 ) = ( x )²
➡ ( 81 ) = ( x )²
➡ √81 = ( x )²
➡ 9 = x
↪ Now,
Perimeter of Rectangle = 2(l+b)
= 2( 40 + 9 )
= 2 × 49
= 98 cm
✔ Hence, perimeter of rectangle is 98 cm.
✔ Let the breadth be x cm
✔ Length of Rectangle ( Base ) = 40 cm
✔ Diagonal ( Hypotenuse ) = 41 cm
✔ Using Pythagoras Theorem
➡ ( H )² = ( A )² + ( B )²
➡ ( 41 )² = ( x )² + ( 40 )²
➡ ( 1681 ) = ( x )² + ( 1600 )
➡ ( 1681 - 1600 ) = ( x )²
➡ ( 81 ) = ( x )²
➡ √81 = ( x )²
➡ 9 = x
↪ Now,
Perimeter of Rectangle = 2(l+b)
= 2( 40 + 9 )
= 2 × 49
= 98 cm
✔ Hence, perimeter of rectangle is 98 cm.
Answered by
0
Sᴏʟᴜᴛɪᴏɴ:
❥︎ ᴀʙ = (41)sǫ - (40)sǫ
➪ 1681 - 1600
☞︎︎︎ 81
✔︎ 9 Cᴍ
Tʜᴇ ᴘᴇʀɪᴍᴇᴛᴇʀ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ = 2(ʟ+ʙ)
= 2(40+9)
= 2×49
= 98
Pʟᴇᴀsᴇ ᴍᴀʀᴋ ᴀs ʙʀᴀɪɴʟɪsᴛ✌︎
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