find the perimeter of rectangle whose length is 40 m and diagonal is 44 .
Answers
Answered by
0
Step-by-step explanation:
As we can see in the rectangle,
By Pythagoras theorem,
Now as given in the question,
Diagonal = 41 cm.
Length = 40 cm.
So, Putting these value we get,
Hence the width of the rectangle is 9 cm.
So
The perimeter of the rectangle = 2 ( Length + Width )
= 2 ( 40 cm + 9 cm )
= 2 x 49 cm
= 98 cm
Hence the perimeter of the rectangle is 98 cm.
Answered by
1
168m
Step-by-step explanation:
perimeter of a rectangle= 2 *(length+breadth)
perimeter =2(40+44)
perimeter= 2*84
perimeter=168
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