Question

Find the perimeter of rectangle whose length is 40and diagonal is 41

Answer 1

Answer:

Step-by-step explanation:

Rectangle

Solve for perimeter

1. P=98

l Length= 40

d Diagonal  =41

Using the formulas

P=2(l+w)

d=w2+l2

Solving forP

P=2l+2d2﹣l2=2·40+2·412﹣402=98

Answer 2

Answer:

98

Step-by-step explanation:

By Pythagoras Property

H^2 = B^2 + P^2

(41)^2 = (40)^2 + P^2

1681 = 1600 + P^2

1681 - 1600 = P^2

81 = P^2

9^2 = P^2

2 will cut with each other

Perimeter -

2 ( L + B )

2 ( 40 + 9 )

2 × 49

98