Find the perimeter of rectangular field whose length is 4times its width and which has area equal to 20736 sq.m.
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area of rectangle=l×b
L is 4 times of B
then
20736=4L×L
L²=5184
L=72cm
B=4×72=288
we Know that
perimeter= 2{L+B]
2(72+288)
2(360)
720cm
L is 4 times of B
then
20736=4L×L
L²=5184
L=72cm
B=4×72=288
we Know that
perimeter= 2{L+B]
2(72+288)
2(360)
720cm
Answered by
6
sorry for my worst handwriting
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