Math, asked by piyushrajpiyush, 1 year ago

find the perimeter of rombus the diagolas is 48cm and 20cm long

Answers

Answered by Aman1215

2

Perimeter of a Rhombus = 2√(p2+q2)
Given,
p=48 q=20
Perimeter of a Rhombus = 2√(482+202)
=2√(2304+400)
=2√(2704)
=2*52
=104 cm2

hope it's help u

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