Find the perimeter of the following triangles.
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The triangle shown in the attachment is an equilateral triangle.
=> PERIMETER of equilateral TRIANGLE = side×3
=> 8 × 3
=> 24 cm
there fore the perimeter of the triangle is 24 cm
=> PERIMETER of equilateral TRIANGLE = side×3
=> 8 × 3
=> 24 cm
there fore the perimeter of the triangle is 24 cm
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Solution :
Given in ∆XYZ
XY = 8cm , YZ =8cm , ZX = 8cm
Perimeter = Sum of the three sides
of given triangle
= XY + YZ + ZX
= 8 cm + 8 cm + 8 cm
= 24 cm
Therefore ,
Perimeter of ∆XYZ = 24 cm
•••••
Given in ∆XYZ
XY = 8cm , YZ =8cm , ZX = 8cm
Perimeter = Sum of the three sides
of given triangle
= XY + YZ + ZX
= 8 cm + 8 cm + 8 cm
= 24 cm
Therefore ,
Perimeter of ∆XYZ = 24 cm
•••••
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